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How to Calculate RC Filter Cutoff Frequency

August 29, 2026 6 min read
Quick answer

An RC filter's cutoff frequency is f_c = 1 / (2 × π × R × C), with R in ohms and C in farads. For example, with R = 1 kΩ and C = 100 nF: f_c ≈ 1,591 Hz ≈ 1.6 kHz. At this frequency the output falls to 0.707× the input (−3 dB).

An RC filter is the most basic filter circuit, using a resistor (R) and a capacitor (C) together to pass some frequencies and attenuate others. The single number that defines its behaviour is the cutoff frequency (fc) — the frequency where the signal power drops to half (−3 dB).

RC filter cutoff formula: fc = 1 / (2πRC)

The cutoff frequency depends only on the resistor and capacitor values:

fc = 1 / (2 × π × R × C)

SymbolMeaningUnit
fcCutoff (corner) frequencyHertz (Hz)
RResistanceOhms (Ω)
CCapacitanceFarads (F)

This formula is the SAME for both first-order low-pass and high-pass RC filters — only the arrangement of R and C differs.

Low-pass or high-pass?

The same two parts make two different filters depending on the layout:

  • Low-pass: R in series, C to ground at the output. Passes frequencies BELOW fc. Used for supply-noise cleanup, PWM→analog.
  • High-pass: C in series, R to ground at the output. Passes frequencies ABOVE fc. Used for DC blocking (capacitor coupling), bass cut.

How to calculate it, step by step

  1. Determine R and C — convert units to base SI (kΩ→Ω, nF→F).
  2. Apply fc = 1 / (2πRC).
  3. To hit a target cutoff, solve in reverse: R = 1/(2π·fc·C) or C = 1/(2π·fc·R).
  4. Pick the nearest standard value and re-check fc.

Worked examples

  • R = 1 kΩ, C = 100 nF: fc = 1 / (2π × 1000 × 100×10⁻⁹) ≈ 1,591 Hz ≈ 1.6 kHz.
  • R = 10 kΩ, C = 10 nF: fc1,591 Hz (same RC product → same fc).
  • Target 1 kHz, C = 100 nF: R = 1/(2π × 1000 × 100×10⁻⁹) ≈ 1.59 kΩ → standard 1.6 kΩ.

What happens at the cutoff? (−3 dB)

At fc the output amplitude falls to 0.707× the input (i.e. −3 dB, half the power) and the phase shifts by 45°. Beyond fc, a first-order filter rolls off at −20 dB/decade (10× attenuation per 10× frequency). For a sharper transition, cascade filters or use an active (op-amp) filter.

Relation to the time constant (τ = RC)

The same RC product gives the time-domain time constant (τ = R × C). The two are linked by fc = 1/(2πτ): a fast circuit (small τ) corresponds to a high cutoff. See also frequency and period.

Common mistakes

  • Unit mix-ups: not converting nF/µF and kΩ to base units (1 nF = 10⁻⁹ F).
  • Forgetting 2π: it is NOT fc = 1/(RC); the angular frequency ω = 1/(RC), but f = ω/2π.
  • Loading: a low-impedance load on the output shifts fc — a buffer may be needed.

Use the calculator

Enter R and C to find the cutoff frequency instantly with our RC Filter Calculator.

Frequently Asked Questions

What is the RC filter cutoff formula?+
f_c = 1 / (2πRC), with R in ohms and C in farads. E.g. 1 kΩ and 100 nF → ≈ 1.6 kHz.
What happens to the output at the cutoff?+
The output falls to 0.707× the input (−3 dB, half power) and the phase shifts by 45°.
Is the formula the same for low-pass and high-pass?+
Yes, f_c = 1/(2πRC) is the same for both; only the arrangement of R and C differs.
How steeply does a first-order RC filter roll off?+
−20 dB/decade (10× attenuation per 10× frequency). For a sharper transition, cascade filters or use an active filter.
How is the time constant related to the cutoff?+
τ = RC and f_c = 1/(2πτ). A small τ (fast circuit) means a high cutoff frequency.